GoGuides Verified Text
OT2
SHA-256 integrity check: match
Source
Encyclopaedia Britannica (1911) / britannica_1911
License
public_domain
Chunk ID
1911:ot2:78926d549b41
Section
Hash Algorithm
sha256
Stored Hash
34d371099fa73b5f639b9db226bc948e072e939080cf5312182b5670140b6589
Computed Hash
34d371099fa73b5f639b9db226bc948e072e939080cf5312182b5670140b6589
Normalizer
ggnorm 1.0
Observed
2026-02-08 18:43:06
Source URL
Verified Text
ot2, be drawn from the fixed point o parallel and equal to the velocities at p, p1, p2 respectively, then the locus of t is the hodograph of the orbits described by p (see figure). from this definition we have the following important fundamental property which belongs to all hodographs, viz. that at any point the tangent to the hodograph is parallel to the direction, and the velocity in the hodograph equal to the magnitude of the resultant acceleration at the corresponding point of the orbit. this will be evident if we consider that, since radii vectores of the hodograph represent velocities in the orbit, the elementary arc between two consecutive radii vectores of the hodograph represents the velocity which must be compounded with the velocity of the moving point at the beginning of any short interval of time to get the velocity at the end of that interval, that is to say, represents the change of velocity for that interval. hence the elementary arc divided by the element of time is the rate of change of velocity of the moving-point, or in other words, the velocity in the hodograph is the acceleration in the orbit. [illustration] analytically thus (thomson and tait, _nat. phil._):--let x, y, z be the coordinates of p in the orbit, [xi], [eta], [zeta] those of the corresponding point t in the hodograph, then [xi] = dx/dt, [eta] = dy/dt, [zeta] = dz/dt; therefore d[xi] d[eta] d[zeta] ---------- = ----------- = ----------- (1). (d^2x/dt^2) (d^2y/dt^2) (d^2z/dt^2) also, if s be the arc of the hodograph, ds / /d[xi]\^2 /d[eta]\^2 /d[zeta]\^2 -- = v = / ( ----- ) + ( ------ ) + ( ------- ) dt \/ \ dt / \ dt / \ dt / / /d^2x\^2 /d^2y\^2 /d^2z\^2 = / ( --- ) + ( --- ) + ( --- ) (2). \/ \dt^2/ \dt^2/ \dt^2/ equation (1) shows that the tangent to the hodograph is parallel to the line of resultant acceleration, and (2) that the velocity in the hodograph is equal to the acceleration. every orbit must clearly have a hodograph, and, conversely, every hodograph a corresponding orbit; and, theoretically speaking, it is possible to deduce the one from the other, having given the other circumstances of the motion. for applications of the hodograph to the solution of kinematical problems see mechanics.